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20x^2-17x-20=0
a = 20; b = -17; c = -20;
Δ = b2-4ac
Δ = -172-4·20·(-20)
Δ = 1889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{1889}}{2*20}=\frac{17-\sqrt{1889}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{1889}}{2*20}=\frac{17+\sqrt{1889}}{40} $
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